x^2-1000x+2100=0

Solution for x^2-1000x+2100=0 equation:

x^2-1000x+2100=0

a = 1; b = -1000; c = +2100;
Δ = b2-4ac
Δ = -10002-4·1·2100
Δ = 991600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{991600}=\sqrt{400*2479}=\sqrt{400}*\sqrt{2479}=20\sqrt{2479}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1000)-20\sqrt{2479}}{2*1}=\frac{1000-20\sqrt{2479}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1000)+20\sqrt{2479}}{2*1}=\frac{1000+20\sqrt{2479}}{2}
$